Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
You find area by multiplying base and height.
The formula is A=bh
so 100=25h
25 times 4 is 100
100=25*4
4cm is your answer
Answer:
Step-by-step explanation:
I guess the angles are supplementary, which means they have a sum of 180º.
11x - 15 + 5x - 13 = 180
16x -28 = 180
16x = 208
x = 13
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
√x+2=3
−4+y=3y+4(y−3)
2+|3x|=2+3
