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viktelen [127]
3 years ago
5

HELPPPPPPPPPPPPPP PLZZZZZZZZZZZ clock arithmetic Will mark brainiest .

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

A) 7

B) 1

C)6

D) 7

Step-by-step explanation:

Clock arithmetic is just like the basic arithmetic you know... with one difference... there are no numbers beyond 12 (or 24).

In your question, you seem to indicate to consider only the 12-hour clock system, much like it is used in the USA.

So, every time you pass 12, you start at 1 again. So, your answer has to be under 13.  If your answer is still > 12 after you subtracted 12, subtract 12 again, and again, and again, until you get something <= 12.

That's what we call a modulo 12.

A) 8 + 11 = 19...  but then you subtract 12... 19 - 12 = 7

B) 4 + 9 = 13, 13 - 12 = 1

C) 7 * 6 = 42, 42 - 12 = 30, 30-12 = 18, 18 -12 = 6

D) 5 * 11 = 55, 55 - 12 = 43, 43 - 12 = 31, 31 - 12 = 19, 19 - 12 = 7

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Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125
kicyunya [14]

Answer:

The  probability is  P(14 <  X  <  20 ) =  0.5354  

Step-by-step explanation:

From the question we are told that

   The  proportion that live with their parents is  \r p  =  0.142

   The  sample  size is n =  125

   

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

  i.e  

       X   \  \~ \ B( \mu ,  \sigma )

Now the mean is evaluated as

      \mu  =  n *  \r p

      \mu  =  125 *  0.142

      \mu  =  17.75

Generally the proportion that are not staying with parents is  

      \r  q  =  1 -  \r  p

= >    \r  q  =  0.858

The standard deviation is mathematically evaluated as

     \sigma  =  \sqrt{n * \r p  *  \r q }

     \sigma  =  \sqrt{ 125 *  0.142 * 0.858  }

    \sigma  = 3.90

Given the n is large  then we can use normal approximation to evaluate the probability as follows  

     P(14 <  X  <  20 ) =  P( \frac{ 14 -  17.75}{3.90}

Now applying continuity correction

      P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < \frac{  X  - \mu }{\sigma } < \frac{ 19.5 -  17.75}{3.90}   )

Generally  

    \frac{  X  - \mu }{\sigma }  =  Z  ( The  \ standardized \ value  \  of  X )

    P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < Z< \frac{ 19.5 -  17.75}{3.90}   )

     P(14 <  X  <  20 ) =  P( -1.0897   < Z<  0.449 }   )

    P(14 <  X  <  20 ) =   P( Z<  0.449   ) - P(Z  <   -1.0897)

So  for the z -  table  

         P( Z<  0.449   ) =  0.67328

         P(Z  <   -1.0897)  = 0.13792

 P(14 <  X  <  20 ) =   0.67328 -  0.13792    

  P(14 <  X  <  20 ) =  0.5354  

     

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