5(3)-3(-2)
15-(-6)=
15+6=21
a negative plus a negative is a positive so its 21
4(3)-3(-2)
12-(-6)
12+6=18
21+18=39

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :
Length of transverse axis is :


length of conjugate axis is :


Equation of hyperbola ~

plug in the values ~


560+ 147= 707
14(40)= 560
14+ 14(1/2)=21
21(7)= 147
Answer:
The answer is C trust me I did this