<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
He rents for d days, but two days are free, so he pays for only d - 2 days.
The rental fee is $45 per day, so for d - 2 days, he pays 45(d - 2). The total he pays is $315, so the equation is
<u>45</u>(<u>d</u> - <u>2</u>) = <u>315</u>
Now we solve the equation to find d, the number of days.
45(d - 2) = 315
45d - 90 = 315
45d = 405
d = 9
The number of days is 9.
Answer: the correct answer is 1/12 ( as a fraction )
Answer:
x = - 5
Step-by-step explanation:
Given
f(x) = - 4x - 10 and f(x) = 10, the equate right sides, that is
- 4x - 10 = 10 ( add 10 to both sides )
- 4x = 20 ( divide both sides by - 4 )
x = - 5
