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3 years ago

|x+3|, if x>5

Mathematics

1 answer:

bearhunter [10]3 years ago

8 0

Answer:

Step-by-step explanation:

Suppose x+3 < 0. Subtract 3 from both sides of the inequality.

x < -3

So, x+3 is negative when x < -3. When x>5,

x+3 > 8, which is positive, so the absolute value function has no effect.

|x+3| > 8

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3 years ago

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3 years ago

I really need help on this problem its on khan academy 27÷(−9)=?

ladessa [460]

Answer: -3

Step-by-step explanation:

$\frac{27}{-9} = -3 \\$

We can check our work my multiplying -3 by -9 and see that it equals 27

$-9*[\frac{27}{-9} = -3 ]* -9\\27 = 27$

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3 years ago

Complete the following statement to illustrate the additive inverse property. 7/9+(-7/9)=?

geniusboy [140]

Answer:

7/9 + (-7/9) = 0

Step-by-step explanation:

Definition of additive inverse:

Two numbers are additive inverses if their sum is zero.

For example, 2 and -2 are additive inverses since 2 + (-2) = 0.

Now your problem:

7/9 + (-7/9) =

7/9 and -7/9 are additive inverses.

Therefore, their sum is 0.

7/9 + (-7/9) = 0

4 0

3 years ago

HEEEEEEEEEEEEEEEEEEEEELP!!!! A line y=mx+b passes through point (16, −10) and is parallel to y=−34x+8.

ycow [4]

Answer:

$b=2$

Step-by-step explanation:

We know that the line passes through the point (16, -10).

And we also know that it is parallel to $y=-\frac{3}{4}x+8$

Notice that the slope of this line is -3/4

Remember that parallel lines have the same slope.

Therefore, the slope of our new line is also -3/4

Now, we can use the point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope and (x₁, y₁) is a point.

So, let’s substitute -3/4 for m and (16, -10) for (x₁, y₁). This yields:

$y-(-10)=-\frac{3}{4}(x-16)$

Distribute:

$y-(-10)=-\frac{3}{4}x+12$

Simplify:

$y+10=-\frac{3}{4}x+12$

Subtract 10 from both sides:

$y=-\frac{3}{4}x+2$

This is in the form y=mx+b.

Therefore, our b is 2.

And our final answer is 2.

5 0

3 years ago