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Ksenya-84 [330]
3 years ago
11

The difference between two numbers is 4. Three times the larger is 2 more than five times the smaller. Find the numbers.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0

Let x represent the larger number.
Let y represent the smaller number.
x-y=4 Given
3x=5y-2 Given 
Now we can just substitute; let x=4+y 
Substitute 4+y for x in the second equation:
3(4+y)=5y-2
12+3y=5y-2
-2y=-14
y=7
Substitute back (into BOTH equations to double check work).
x, the larger number, is 11 
Anon25 [30]3 years ago
7 0
Da numbers are x and y

lets say x>y
differebec between x and y is 4
x-y=4


3 times the larger is 2 more than 5 times the smaller
3 times x is 2 more than 5 times y
3x=2+5y

ok so we gots
x-y=4 and
3x=2+5y

hmm
in the first one we can solve for x and subsitute
x-y=4
add y to both sides
x=y+4
subsitute y+4 for x

3x=2+5y
3(y+4)=2+5y
distribute
3y+12=2+5y
minus 3y both sides
12=2+2y
minus 2 both sides
10=2y
divide 2 both sides
5=y

subsitute back

x=y+4
x=5+4
x=9

the numbers are 9 and 5
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Find the polynomial of minimum degree, with real coefficients, zeros at x=4±2⋅i and x=−8, and y-intercept at −480. Write your an
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Answer:

The polynomial of minimum degree is p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480.

Step-by-step explanation:

According to the statement, we appreciate that polynomial pass through the following points:

(i) (4 + 2\,i,0), (ii) (4 - 2\,i, 0), (iii) (-8, 0), (iv) (0, -480)

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p(x) = (x-4-2\,i)\cdot (x-4+2\,i)\cdot (x+8)\cdot (x-r_{1})

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p(x) = (x^{2}-4\cdot x-2\,i\cdot x-4\cdot x +16+8\,i+2\,i\cdot x-8\,i+4)\cdot (x+8)\cdot (x-r_{1})

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p(x) = (x^{3}-8\cdot x^{2}+20\cdot x +8\cdot x^{2}-64\cdot x+160)\cdot (x-r_{1})

p(x) = (x^{3}-44\cdot x +160)\cdot (x-r_{1})

If we know that p (0) = -480, then:

-480=160\cdot (-r_{1})

-160\cdot r_{1} = -480

r_{1} = 3

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p(x) = (x^{3}-44\cdot x +160)\cdot (x-3)

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p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480

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