Answer:
the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Step-by-step explanation:
From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.
Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:







Thus; the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Answer:(9y-7)(9y+7)
Step-by-step explanation:
81y^2-49
=(9y)^2-(7)^2
=(9y-7)(9y+7)
4y + 228 = 352
4y = 352 - 228
4y = 124
--- ----
4 4
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| y = 31 |
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hope this helps
Answer:
Step-by-step explanation:
Flat rate is the y- intercept b = 11.2
Charge per mile is the slope m = 3.1
<u>The equation is:</u>
Step-by-step explanation:
since packages are similarsimilar packages. The ratio of the volumes is 8:125. Determine the dimensions of the bigger package. The dimensions of the smaller package are... Height= 45cm, Length= 80cm, and Width= 25cm.
Length of bigger package = <em><u>8</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>c</u></em><em><u>m</u></em>
Width of bigger package =<em><u>2</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>3</u></em><em><u>9</u></em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>2</u></em><em><u>5</u></em><em><u>c</u></em><em><u>m</u></em>
Height of bigger package =<em><u>4</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>7</u></em><em><u>0</u></em><em><u>3</u></em><em><u>.</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>cm</u></em>