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Fynjy0 [20]
3 years ago
10

(I need some help please do if you can) ʕ•ᴥ•ʔ

Mathematics
1 answer:
Harrizon [31]3 years ago
6 0

Answer:

90.4 feet (nearest tenth)

Step-by-step explanation:

Please see attached picture for full solution.

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Identify the coefficient of -z
harina [27]

Answer:

-1

Step-by-step explanation:

Your welcome back to the inputs is

6 0
3 years ago
I need help 50 pts plz asap
expeople1 [14]

Answer:

c

Step-by-step explanation:

a: 9/5 and 19/10 are already in simplest form

b:25/35 can be simplified to 5/7 if you divide each side by 5 and 20/24 can

  be simplified to 5/6 if you divide each side by 4

c: both 15/10 and 21/14 can be simplified to 3/2

d: 4/6=2/3 and 10/16=5/8

3 0
3 years ago
Read 2 more answers
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Svetllana [295]

The equation x^{2} -4=0~~and~~4x^2=16 are true for  x = -2 and x = 2.

The given equations are given as:

x^2-4=0\\\\x^2=-4\\\\3x^2+12=0\\\\4x^2=16\\\\2(x-2)^2=0

We need to select two equations that are true for x = -2 and x = 2.

<h3>What are the solutions to an equation ?</h3>

The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.

Example:

x - 2 = 2

Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.

4 - 2 = 2

2 = 2

Let's find the solutions for each equation.

1.

x^2 - 4=0

x^{2} = 4

x = \sqrt{4} = ± 2

x = = 2 and x = -2

2.

x^2 =-4

x = \sqrt{-4}

x = \sqrt{-1 \times 4} = \sqrt{-1}\times\sqrt{4}

x = ± 2 \sqrt{-1}

x = 2i and x = -2i         where i = \sqrt{-1}

3.

3x^{2} + 12  = 0

x^{2} = -12 / 3 = -4

x = \sqrt{-1} \sqrt{4}

x = ± 2\sqrt{-1}

x = 2i and x = -2i

4.

4x^{2} = 16

x^{2} = 16 / 4

x^{2} = 4

x = \sqrt{4}

x = ±2

x = 2 and x = -2

5.

2(x-2)^2 = 0

(x-2)^2 = 0

x - 2 = 0

x = 2.

Thus the equation x^{2} -4=0~~and~~4x^2=16 have solutions x = -2 and x = 2.

Learn more about solutions of equations here:

brainly.com/question/14506845

#SPJ1

4 0
2 years ago
Rewrite the rational exponent as a radical expression. 3 to the 2 over 3 power, to the 1 over 6 power
professor190 [17]

Answer:

the ninth root of 3

Step-by-step explanation:

3 to the 2 over 3 power, to the 1 over 6 power rewritten as a radical expression is ''the ninth root of 3''.

Hope this helps!

5 0
3 years ago
H(x)=-7x-11 when x=7
Eva8 [605]

Answer:

-60

Step-by-step explanation:

h(x)=-7x-11

h(7)=-7(7)-11

h(7)=-49-11

h(7)=-60

5 0
3 years ago
Read 2 more answers
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