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Marysya12 [62]
3 years ago
13

Help!! Which of the following best represents Z1 • Z2 select all that apply

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)

z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}

\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\

Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)

On simplifying, we get

Z_1* Z_2 =-3\sqrt{2}

<h2>Therefore, correct option is  1st option.</h2>
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Use implicit differentiation to find the negative slope of a tangent to the circle x^2+y^2=16 at x=-2
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3 0
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