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3 years ago

Who knows Brent Rivera's phone number????

Mathematics

2 answers:

iragen [17]3 years ago

4 0

Answer:

not me

Step-by-step explanation:

Tanya [424]3 years ago

3 0

The hype house does

You might be interested in

Determine the approximate ordered pair for f(x) = g(x). the graph of two linear functions negative 4 times x plus 15 times y equ

melisa1 [442]

Answer:

(x, y) ≈ (2.848, -19.241)

Step-by-step explanation:

I find it much easier to work with the problem statement when math expressions are written using numbers and symbols. We assume you have ...

-4x +15y = -300

20x +4y = -20

Dividing the second equation by 4 and subtracting the x-term gives ...

y = -5-5x

Substituting that into the first equation, we get ...

-4x +15(-5-5x) = -300

-79x -75 = -300

x = -225/-79 = 2 67/79 ≈ 2.8481

Substituting this into the equation for y gives ...

y = -5(x +1) = -5(3 67/79) = -19 19/79 ≈ -19.2405

The approximate solution is ...

(x, y) = (2.8481, -19.2405)

3 0

3 years ago

Find the value of x given that the mean is 6: 2, 8, 9, 7, 6, x

Novosadov [1.4K]

Answer:

Step-by-step explanation:

(32 + x)/6=6

8 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago

. Dillion deposits $150 into his account. One week later, he withdraws $26. Write an addition expression to represent this situa

Lina20 [59]

Answer:

$Expression = x + 150 +(- 26)$

$124 higher

Step-by-step explanation:

Given

$Deposit = \$150$

$Withdrawal = \$26$

Required

Represent the situation

Determine how much higher or lower is the remaining amount

Let the initial amount in his account be represented with x

When he deposited, the balance becomes

$Balance = x + 150$

When he withdrew, the balance becomes

$Balance = x + 150 + (-26)$

Hence, the algebraic expression is

$Expression = x + 150 +(- 26)$

Calculating how much higher or lower

$Balance = x + 150 + (-26)$

Open bracket

$Balance = x + 150 -26$

$Balance = x + 124$

Recall that the initial amount in the account is x

The difference between the balance and the x is as follows

$Difference = x + 124 - x$

$Difference = \$124$

Hence, the account has a higher of $124 after both transactions

8 0

3 years ago

Round to the near at tenth | 3x + 1 | =22

sdas [7]

Answer:

x =7 x = -7 2/3

Step-by-step explanation:

| 3x + 1 | =22

Absolute value equations have 2 solutions, one positive and one negative

3x+1 = 22 3x+1 = -22

Subtract 1 from each side

3x+1-1 =22-1 3x+1-1 = -22-1

3x= 21 3x = -23

Divide each side by 3

3x/3 = 21/3 3x/3 = -23/3

x =7 x = -7 2/3

6 0

3 years ago