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olga55 [171]
3 years ago
10

At an amusement park, the probability that a child eats popcorn and cotton candy is 0.58. The probability that a child eats popc

orn is 0.69 and the probability that a child eats cotton candy is 0.87. What is the probability (rounded to the nearest hundredth) that a child eats popcorn given that the child has already eaten cotton candy?
Hint:
P(A|B)=P(A∩B) / P(B)

0.84

0.67

0.79

0.40
Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

<u>Answer:</u>

The correct answer option is 0.67.

<u>Step-by-step explanation:</u>

We are given that the probability that a child eats popcorn and cotton candy is 0.58, probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87.

We are to find the probability that a child eats popcorn given that the child has already eaten cotton candy.

P (eats popcorn and has already eaten cotton candy) = \frac{0.58}{0.87} = 0.67

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