Question

At an amusement park, the probability that a child eats popcorn and cotton candy is 0.58. The probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87. What is the probability (rounded to the nearest hundredth) that a child eats popcorn given that the child has already eaten cotton candy?
Hint:
P(A|B)=P(A∩B) / P(B)

0.84

0.67

0.79

0.40

Answer 1

Answer:

The correct answer option is 0.67.

Step-by-step explanation:

We are given that the probability that a child eats popcorn and cotton candy is 0.58, probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87.

We are to find the probability that a child eats popcorn given that the child has already eaten cotton candy.

P (eats popcorn and has already eaten cotton candy) = $\frac{0.58}{0.87}$ = 0.67