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vova2212 [387]
3 years ago
7

Find the sum of the geometric series:

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}
\end{cases}\\\\
-------------------------------

\bf \sum\limits_{i=1}^{5}~\stackrel{a_1}{375}\stackrel{r}{\left( \frac{-1}{5} \right)}^{i-1}\qquad 
\begin{cases}
a_1=375\\
r=-\frac{1}{5}
\end{cases}\implies S_5=375\left( \cfrac{1-\left(  \frac{-1}{5}\right)^5}{1-\left(  \frac{-1}{5}\right)} \right)


\bf S_5=375\left( \cfrac{1-\left( \frac{-1}{3125} \right)}{1+\frac{1}{5}} \right)\implies S_5=375\left( \cfrac{1+\frac{1}{3125}}{1+\frac{1}{5}} \right)
\\\\\\
S_5=375\left( \cfrac{\frac{3126}{3125}}{\frac{6}{5}} \right)\implies S_5=375\left(\cfrac{3126}{3125}\cdot \cfrac{5}{6}\right)\implies S_5=375\left(\cfrac{521}{625}\right)
\\\\\\
S_5=\cfrac{1563}{5}\implies S_5=312\frac{3}{5}
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