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3 years ago

In the multiplication sentence below, which numbers are the factors? Check

Mathematics

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

The factors are 7 and 3

Step-by-step explanation:

The factors of a multiplication sentence are the numbers that are being multiplied for the product (or answer).

You might be interested in

Express 80 as the product of its prime factors. Write the prime factors in ascending order.

stepan [7]

Answer:

the answer of that is 16 x 5

Step-by-step explanation:

7 0

1 year ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

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valentinak56 [21]

Step-by-step explanation:

$\huge \: 2 \sqrt{x} .4 {x}^{ - \frac{5}{2} } \\ \\ \huge \: = 2.4 {x}^{ \frac{1}{2} } . {x}^{ - \frac{5}{2} } \\ \\ \huge \: = 8 {x}^{ \frac{1}{2} - \frac{5}{2} } \\ \\ \huge \: = 8 {x}^{ \frac{1 - 5}{2} } \\ \\ \huge \: = 8 {x}^{ - \frac{4}{2} } \\ \\ \huge \: = 8. {x}^{ - 2} \\$

4 0

3 years ago

Find an equation for the line tangent to the circle x^2 +y^2=25 at the point (3, -4)

Lostsunrise [7]

Hello :
the center of this cercle is : O( 0, 0)
calculate the slope m of the line : OA .. A (3,-4)
m= (yA - yO) / (xA- xO)
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1 (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)

7 0

3 years ago

Solve using the substitution method 8x-2y=-14 5x+y=33 show work

SOVA2 [1]

13x - y = 19
-y = - 13x + 19
y = 13x + 19

8 0

2 years ago