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Scilla [17]
3 years ago
15

What is the answer to the pic​

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

7

Step-by-step explanation:

\frac{7^{-1}}{7^{-2}}

7^{-1-(-2)}

7^{-1+2}

7^{1}

7

I used the following rules:

\frac{a^m}{a^n}=a^{m-n}

a^1=a

a \neq 0

You might be interested in
The vertices of a rectangle are R(–5, –5), S(–1, –5), T(–1, 1), and U(–5, 1). After translation, R' is the point (–11, –11). Fin
koban [17]

Answer:

The original coordinate of

R is (-5, -5)

The new coordinate of

R is (-11, -11)

The translation rule is ( x - 6, y - 6)

The original coordinate of

U is (-5, 1)

The new coordinate of

U is (-5 - 6, 1 - 6)

which is

(-11, -5)

U' = (-11, -5)

7 0
3 years ago
Solve the equation 7x+4=32​
Vlad [161]

Answer:

x=4

Step-by-step explanation:

32-4=28

28÷7= 4

x=4

5 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
4 years ago
1,3,5 are there first three term of the first differences of a quadratic equation. the 7th term of the quadratic sequence is 35​
jeka57 [31]

Answer:

2n-1

Step-by-step explanation:

Not sure what you needed but here is the nth term.

6 0
3 years ago
11/15 + (-5 1/2) I know the answer is -4 23/30 but I can't get it. I've done this so far:
NeX [460]


It helps me to convert the fractions into decimals, so 11/15=.73 and -5 1/2= -5.5.

Next, just add -5.5 to .73, you should get -4.77, then convert that back to a fraction and get -4 23/30 :)

6 0
3 years ago
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