3 years ago

HELPPPP!!! and get brainliest!!!!!!! + 22 points

Mathematics

1 answer:

ella [17]3 years ago

8 0

Answer:

Step-by-step explanation:

b/c the function goes thur the point (1,4) we know it's 4 times more than f(x) so g(x) = 4 $x^{2}$

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Find all real solutions and show work: <br> 2x^3-3x^2+18x-27=0

Amiraneli [1.4K]

Given:

The given equation is

$2x^3-3x^2+18x-27=0$

To find:

All the real solutions.

Solution:

We have,

$2x^3-3x^2+18x-27=0$

It can be written as

$x^2(2x-3)+9(2x-3)=0$

$(2x-3)(x^2+9)=0$

Using zero product property, we get

$(2x-3)=0$ and $(x^2+9)=0$

$2x=3$ and $x^2=-9$

$x=\dfrac{3}{2}$ and $x=\pm\sqrt{-9}$

We know that $x=\pm\sqrt{-9}$ is an imaginary number because there is a negative sign under the square root.

Therefore, $x=\dfrac{3}{2}$ is the only real solution of the given equation.

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Answer:

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Step-by-step explanation:

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Liam biked for 3 hours at a speed of 8 mph and then walked the remaining part of his way at a speed of 3 mph. If the total dista

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Answer:

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Step-by-step explanation:

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First lets simplify both side of this equation.
2 + 7 + ♢ = 3 + 6 + 5
Subtract 9 from both sides of the equation.
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Answer (C)
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