Answer:
n ÷ 5 < 4
Step-by-step explanation:
Quotient is to divide.
Let n be the unknown number.
Now you have the equation needed.
<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
1) Circumference of Earth: Diameter x π → 12,800 x π = 40,212.39 km
2) time in Hour = distance/speed → distance = 40,212.39 and speed = 2 Mi/h
1st: convert miles into km : 1 mile = 1.609344 km and 2 miles = 3.218688 km
2nd: convert speed into km/h → speed = 3.218688 km/h
And time in hour = 40,212.39 / 3.218688 → time = 12,493 hours OR in days:
12,493 / 24 = 521 days (OR 104 weeks, including 2 days of rest)
Answer:
y=mx+b
Step-by-step explanation:
Answer:
m∠1 = 60°
m∠2 = m∠4 = 39°
m∠3 = m∠5 = 21°
Step-by-step explanation:
ΔWXY is a equilateral angle,
Therefore, all angles of the the triangle are equal in measure.
m∠W + m∠X + m∠Y = 180°
3m∠W = 180°
m∠W = 60°
Since, ΔWZY is an isosceles triangle,
m∠3 = m∠5
m∠3 + m∠Z + m∠5 = 180°
m∠3 + 138° + m∠3 = 180°
2m∠3 = 180 - 138
m∠3 = 21°
Therefore, m∠3 = m∠5 = 21°
Since, m∠2 + m∠3 = 60°
m∠2 = 60 - 21
= 39°
Since, m∠4 + m∠5 = 60°
m∠4 = 60 - 21
= 39°
m∠1 = 60°
