Three of the four towns are on the vertices of the triangle ΔCBD, through
which the bearing can calculated.
<h3>Response:</h3>
- The bearing of D from B is approximately <u>209.05°</u>
<h3>Method by which the bearing is found;</h3>
From the given information, we have;
AC = AB = 25 km
∠BAC = 90° (definition of angle between north and east)
ΔABC = An isosceles right triangle (definition)
∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)
The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the
direction of <em>D.</em>
<em />
Therefore;
- The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>
Learn more about bearings in mathematics here:
brainly.com/question/10710413
Answer:
<h2>
<u>I HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIPI HAVE CLUB PENGUIN MEMBERSHIP</u></h2>
Step-by-step explanation:
Alright so if you have a negative number let's say -5 if you put the absolute value symbols around it like so |-5| then it becomes positive. Whatever is in the lines becomes positive, that's why I call it the positive box. It describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The number is never negative
