Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
- Parallel lines will always have the same slope but different y-intercepts.
<u>1) Determine the slope of the parallel line</u>
Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

Switch the sides

Divide both sides by 2 to isolate y

Now that this equation is in slope-intercept form, we can easily identify that
is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope
. Plug this into
:

<u>2) Determine the y-intercept</u>

Plug in the given point, (4,0)

Subtract both sides by 6

Therefore, -6 is the y-intercept of the line. Plug this into
as b:

I hope this helps!
Answer:
BD = 16
Step-by-step explanation:
By applying mean proportional theorem in the given right triangles,

AD × CD = BD²
8 × 32 = BD²
BD = √256
BD = 16
Therefore, measure of side BD = 16 units.
What are you asking here? I need more information to solve please
Answer:
<h2>y = 4x + 4</h2>
Step-by-step explanation:
The slope-intercept form:

m - slope
b - y-intercept
Parallel lines have the same slope.
We have y = 4x + 2 → m = 4.
The slope of parallel line is m = 4 and the y-intercept b = 4.
Therefore we have the equation of a line:

Answer: The correct option is figure (1).
Explanation:
Reason for correct option:
The figure (1) shows the reflection across the side XY followed by reflection across the side YT.
When we reflect the triangle XYZ across the side XY we get the triangle XYT as shown in below figure.
After that we reflect the triangle XYT across the side YT and we get the triangle PYT.
Therefore, only figure 1 shows the triangle pairs can be mapped to each other using two reflections.
Reason for incorrect options:
The figure (2) shows the rotation of 180 degree along the point y.
The figure (3) shows the reflection across the side XY followed by the translation.
The figure (4) shows the reflection, followed by rotation , followed by translation.