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3 years ago

Sean dives a depth of 73feet. What is the correctway to show how far Seandove?

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

6 0

Answer:

To find distance use this equation and plug the variables you have in it.

Equation: Distance=Rate×Time

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Evaluate 6(-3) -1-51 +131 = -20 -10 16

Archy [21]

6(-3)-1-51+131=
-18-1-51+131=
-70+131=61

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3 years ago

Solve this system of equations by

makvit [3.9K]

Answer:

x=4 and y=11

Step-by-step explanation:

x+y=15

5x-y=9

x+5x-y+y=15+9

6x=24

X=4

x+y=15

4+y=15

y=11

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3 years ago

. Simplify: (2 x 2 + 6-10 ÷ 2)

Maurinko [17]

Answer: 5

Step-by-step explanation:

You see 2x2 = 4 right and since this is operation 2 / 10 = 5 and 6-5 = 1 so add 1 and that gives you 5

2x2 = 4 / 10/2 = 5 / 6-5 = 1 +4 = 5

7 0

3 years ago

Read 2 more answers

Please help me with geometry

spayn [35]

For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

------------------------------------------------------

For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

------------------------------------------------------

For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

------------------------------------------------------

For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

------------------------------------------------------

For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

------------------------------------------------------

For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

------------------------------------------------------

For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

------------------------------------------------------

For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

------------------------------------------------------

For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

------------------------------------------------------

See the attached image for how the answers match up (take note of the letter labels)

3 0

4 years ago

A soccer league has 25 sixth graders, 20 seventh graders, and 15 eighth graders. What is the ratio of 7th and 8th graders to 6th

neonofarm [45]

Answer:

35:25

Step-by-step explanation:

seventh and eighth to sixth

7th+8th : 6th

20+15 : 25

35:25

4 0

3 years ago

Sean dives a depth of 73feet. What is the correctway to show how far Seandove?​

Sean dives a depth of 73feet. What is the correctway to show how far Seandove?