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3 years ago

How do you rewrite expressions using a positive exponent when the exponent originally attached is negative/fraction?

Mathematics

1 answer:

aleksley [76]3 years ago

7 0

Answer:

Step-by-step explanation:

Take the negative exponent in the denominator to make it positive

Example = (2^-3)

= 1/2³

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NeTakaya

To do groups of 9, she could make 2 rows of 9. To do 3, she could do 6 rows of 3. Last, to do 6 she could do 3 rows of 6. :)

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3 years ago

Read 2 more answers

When a polynomial is divided by (x+2), the remainder is -19. When the same polynomial is divided by (x-1), the remainder is 2. D

NeTakaya

<h3>Answer: 7x - 5</h3>

============================================

Explanation:

We're dividing some unknown polynomial P(x) over (x+2) to get a quotient Q1(x) and remainder -19. That must mean

P(x)/(x+2) = Q1(x) - 19/(x+2)

P(x) = Q1(x)*(x+2) - 19

Note that plugging in x = -2 leads to P(-2) = -19. This is an example of the remainder theorem.

Similarly,

P(x) = Q2(x)*(x-1) + 2

since dividing by (x-1) leads to a remainder of 2. We have P(1) = 2.

We'll use P(-2) = -19 and P(1) = 2 in the later sections below.

----------------

We want to find the value of r such that

P(x) = Q3*(x+2)(x-1) + r

Let's say that r = ax+b

Meaning we now have

P(x) = Q3*(x+2)(x-1) + r

P(x) = Q3*(x+2)(x-1) + ax+b

The goal from here is to find 'a' and b so we can get the remainder ax+b.

----------------

Plug in x = -2 and solve for b.

P(x) = Q3*(x+2)(x-1) + ax+b

P(-2) = Q3*(-2+2)(-2-1) + a(-2)+b

-19 = Q3*(0)(-3)-2a+b

-19 = -2a+b

b = 2a-19

----------------

Plug in x = 1 to get...

P(x) = Q3*(x+2)(x-1) + ax+b

P(1) = Q3*(1+2)(1-1) + a(1)+b

P(1) = a+b

2 = a+b

a+b = 2

a+(2a-19) = 2 .... plug in b = 2a-19

3a-19 = 2

3a = 19+2

3a = 21

a = 21/3

a = 7

Use that value to find b

b = 2a-19

b = 2(7)-19

b = 14-19

b = -5

----------------

We found that a = 7 and b = -5.

The remainder ax+b updates to the final answer 7x-5

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3 years ago

Factor the expression.

tiny-mole [99]

B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out. When you check B you get $k^{2} -5kf+10kf- 50f^{2}$ combine your like terms and you have your original expression of $k^{2} +5kf-50 f^{2}$

Hope that helps

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4 years ago

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prohojiy [21]

Answer:

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Step-by-step explanation:

It is between 2 congruent angles therefore bisects those angles

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