Answer:
a(n)=1.15[a(n-1)]
Step-by-step explanation:
we know that
Let
a0 -----> the length of the original copy
<em>The first copy is equal to</em>
a1=1.15(a0)
<em>The second copy is </em>
a2=1.15[1.15(a0)] or a2=1.15[a1]
<em>The third copy is</em>
a3=1.15{1.15[1.15(a0)]} or a3=1.15[a2]
therefore
A recursive formula will be
a(n)=1.15[a(n-1)]
Answer:
240
Step-by-step explanation:
Answer:
A - B = [ -1 3 ]
[ -6 2 ]
[ -4 -10 ]
Step-by-step explanation:
Since Matrix A and Matrix B have the same size, then we can simply perform the operation of subtraction on each position within the matrices to get the resulting subtracted matrix.
A = [ 4 7 ] B = [ 5 4 ]
[ -3 8 ] [ 3 6 ]
[ -5 -2 ] [ -1 8 ]
A - B = [ (4 - 5) (7 - 4) ]
[ (-3 - 3) (8 - 6) ]
[ (-5 - -1) (-2 - 8) ]
A - B = [ -1 3 ]
[ -6 2 ]
[ -4 -10 ]
Cheers.
The product of any number and its reciprocal is ' 1 '.
Call the number ' Q '.
Whatever the number is, its reciprocal is 1/Q .
Their product is
( Q ) x ( 1/Q ) = ( Q/Q ) = 1
