Answer:
A. moving forward for 10m at a steady pace of 2m/s
B. moving backwards 8m at a steady pace of 2.67m/s
C. staying in the same spot for 4 seconds
D. moving 9m at a steady pace of 4.5m/s
E. moving 4.5m with an <u><em>average</em></u><em> </em>pace of 1.5m/s
Answer:
(or 6.25)
Step-by-step explanation:
Let's do a simple square problem to see the relationship between the elements of the resulting equation...

As you see, the number of 'x' (6) is the double of the numeric part of the binomial expression (3), while the numeric-only part (9) is the square of the numeric part of the binomial expression (3).
So, if we look at the formula from the problem, we see the the number of 'x' is 5. To obtain the C value, we need to divide the 5 by 2... then get the square value of the result.
(or 6.25)
Answer:
Step-by-step explanation:
Use the formula for the area of a triangle,
Area of a triangle = 
7). Area of the triangle = 
= 74 km²
8). Area of the triangle = 
= 30.8 cm²
9). Area of the triangle = 
= 56 m²
10). Area of the triangle = 
= 42.35 km²