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Alex17521 [72]
3 years ago
6

I have no parallel sides and my diagonals are perpendicular. Which quadrilateral am I?

Mathematics
1 answer:
alexdok [17]3 years ago
7 0
Cylinder
hope that this helps you. =)
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Solve for x please.
andrew-mc [135]

Answer:

x=6

Step-by-step explanation:

A circle equals 360 degrees.  There are 3 parts in this circle.

26x-6 + 17x+1 + 107 = 360

Combine like terms

43x +102 = 360

Subtract 102 from each side

43x +102-102 = 360-102

43x = 258

Divide by 43

43x/43 = 258/43

x =6

8 0
3 years ago
Let two cards be dealt successively, without replacement, from a standard 52-card deck Find probability of the event hear dealt
Marianna [84]

Answer:

12/51

Step-by-step explanation:

There are 13 cards for each shape in a 52-card deck

If the first card is a heart, that means the probability is 13/52 = 1/4

If the second card is a heart, that means the probability is 12/51.

6 0
4 years ago
Find the Area of a regular polygon pentagon with a side of 6m
frosja888 [35]
Here is the answer

A≈61.94cm²
3 0
4 years ago
What does x and y =??????
Kazeer [188]

Answer:

x=30. y=60

Step-by-step explanation:

DG is a straight segment so it sums to 180 degrees. ECG is a right angle so 90 degrees. The rest is described as 2x and x. So 3x=90 degrees. x=30. Eh is also a straight segment. since we know x, we know that ECD is 60 degrees. So y+y=120 degrees. 2y=120. y=60.

6 0
3 years ago
Derive the equation of the parabola with a focus at (-2,4) and a directrix of y=6 . Put the equation in standard form
Maru [420]

Answer:

y =  -  \frac{1}{4}  {(x + 2)}^{2}  + 5

Step-by-step explanation:

The vertex of this parabola is the midpoint of the focus (-2,4) and where the directrix intersects the axis of symmetry of the parabola (-2,6)

This parabola must open downwards due to the position of the directrix and has equation of the form:

{(x - h)}^{2}  =  - 4p(y - k)

where (h,k) is the vertex.

This implies that:

h =  - 2

and

k =  \frac{4 + 6}{2}  = 5

The value of p is the distance from the vertex to the focus:

p =  |6 - 5|  = 1

We substitute all the values into the formula to get:

(x -  - 2)^{2}  =  - 4(1){(y  - 5)}

{(x  + 2)}^{2}  =  - 4(y - 5)

Or

y =  -  \frac{1}{4}  {(x - 5)}^{2}  + 5

4 0
3 years ago
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