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Harlamova29_29 [7]
3 years ago
10

What is the common multiples of 5,3,8

Mathematics
2 answers:
vovikov84 [41]3 years ago
5 0

Answer:

<h2>120</h2>

Step-by-step explanation:

3, 5 and 8 are Relatively prime numbers (LCD(3, 5, 8) = 1).

Therefore LCM(3, 5, 8) = 3 · 5 · 8 = 120

tangare [24]3 years ago
3 0

Answer:

120.

Step-by-step explanation:

If you're asking for LCM the answer is 120.

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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
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Answer:

(1)Equivalence Relation

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(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
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(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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