Answer:
15
proof on pic......................
log_10 (600) is between 2 and 3
2,77815
Answer:
since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Step-by-step explanation:
Given that the data in the question;
p" = 13/20 = 0.65
Now the test hypothesis;
H₀ : p = 0.9
Hₐ : p < 0.9
Now lets determine the test statistic;
Z = (p" - p ) / √[p×(1-p)/n]
= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]
= -0.25 / √[0.9 × 0.1 / 20 ]
= -0.25 / √0.0045
= -0.25 / 0.067
= - 3.73
Now given that a = 0.05,
the critical value is Z(0.05) = 1.645 (form standard normal table)
Now since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
The horse traveled 439.6 feet after walking around the track 5 times
<u><em>Solution:</em></u>
Given that, horse walks around a circular track while its trainer stands in the center
The trainer is 14 feet from the horse at all times
Therefore, radius of circular track = 14 feet
The circumference of circle is the distance traveled by horse for 1 lap
<em><u>The circumference of circle is given as:</u></em>

Where, "r" is the radius and
is a constant equal to 3.14

Thus the distance traveled by horse for one time in circular track is 87.92 feet
<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>
Multiply the circumference by 5

Thus the horse traveled 439.6 feet after walking around the track 5 times