You haven't told me what the question is. But I put the mouse
to my forehead, closed my eyes, took a deep breath, and I could
see it shimmering in my mind's eye. It was quite fuzzy, but I think
the question is
"What score does Andrew need on the next test
in order to raise his average to 72% ?"
The whole experience drew an incredible amount of energy
out of me, and the mouse is a total wreck. So we'll just go ahead
and answer that one. I hope it's the correct question.
The average score on 4 tests is
(1/4) (the sum of all the scores) .
In order for Andrew to have a 72% average on 4 tests,
the sum of the 4 scores must be
(4) x (72%) = 288% .
Out of that total that he needs, he already has
(64% + 69% + 73%) = 206%
on the first three tests.
So in order to average 72% for all 4 tests,
he'll need to score
(288% - 206%) = 82%
on the fourth one.
Answer:-1
Step-by-step explanation:You do reverse operation so negative 2Y means multiplication so you divide two -2 sides so positive two divided by -2 is -1
The ascending or descending order of a polynomial is
determined by the increasing or decreasing power of variable “x” respectively.
<span>The question is to find about the polynomial in
descending order, so in this case, the 3rd option is correct, i.e.
4x^2 – 3x + 9 or 4x^2 – 3x^1 +9x^0. The power of “x”
decreasing from 2 to 1 and then finally to 0.</span>
The first one is -5,-3 ab.
Answer:
(x-1)^2+(y+1)^2=3
Step-by-step explanation:
x² + y2 - 2x + 2y - 1 = 0
add the 1 to get it to the other side of the equation
x² + y2 - 2x + 2y = +1
group the x's and y's
(x² -2x) + (y2+2y) = +1
then you'll complete the square on the -2x and + 2y. that just means divide by two and then raise it to the 2nd power.
so (-2/2)^2 and (+2/2)^2
(x²-2x+1)+(y2+2y+1) = 1+1+1
you add the one's to the other side because whatever is done to one side must be done to the other
you'll then need to factor again.
(x-1)^2+(y+1)^2=3
to factor it take one of your squared x's, the sign of the middle term within the parentheses , then the square root of the last term within the parentheses. remeber to put your ^2 (raised to the 2nd power) outside of the parentheses when you finish.
