Answer: The 1st one is 1 soultion the 2nd one is 1 soultion the 3rd one is multiple soultion and the last one is multiple solution
Step-by-step explanation: hope I am right?
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
(half * base 1 * base 2)/height
base 1 is 6 and base 2 is 9
get the height from similarity
6/9 = 8/CE
therefore CE = 72/6
Answer:
f(-2)=4+6+2
f(-2)=12
Step-by-step explanation:
Add -2 where all the x values are then solve
