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Olegator [25]
3 years ago
7

Please help me with this please

Mathematics
2 answers:
zheka24 [161]3 years ago
4 0

Answer:

the answer would be 14

Step-by-step explanation:

The table is going by 4's

erastovalidia [21]3 years ago
3 0

Answer:

the answer is 14 so I need jdjdjrjrjrekeiwodbf jcjcix

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What is the value of x?
elena-14-01-66 [18.8K]
The median has the property of being equal to 1/2 the length of the 2 parallel lines in a trapezoid. In this case. 1/2 [(x + 8) + (5x + 4)] = 24 There is your equation. Now all you have to do is solve it.

1/2 (x + 8 + 5x + 4) = 24 I've removed the inner brackets.
1/2 (6x + 12) = 24 Gathered like terms.
(6x + 12) = 24*2 Multiplied both sides by 2
6x + 12 = 48 removed the brackets.
6x = 48 - 12 subtracted 12 from both sides.
6x = 36 Divide by 6
x = 36/6
x = 6

6 <<< answer.
6 0
3 years ago
Find the value of the unknown side length for the given perimeter P. P = 14 m A. 3 m B. 4 m C. 14 m D. 25 m
koban [17]
If the perimeter is 14. Add 2,4, and 5 which is 11. Then find out how many meters does it take to get from 11 to 14. In this case the answer is 3
5 0
3 years ago
Chef bought 3 3/4 kilograms of apples 7 1/4 kilograms of pears and 10 1/8 kilograms of oranges. How many kilograms of fruit is a
Hatshy [7]

Answer: 21 1/8 kilogram

Step-by-step explanation:

From the question, we are informed that Chef bought 3 3/4 kilograms of apples 7 1/4 kilograms of pears and 10 1/8 kilograms of oranges. The total kilogram of fruits bought would be:

= 3 3/4 + 7 1/4 + 10 1/8

Note that the Lowest Common Multiple is 8.

= 3 6/8 + 7 2/8 + 10 1/8

= 20 9/8

= 21 1/8 kilogram

6 0
3 years ago
If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
Which line is parallel to 8x+2y=12
Nat2105 [25]

x=3/2-1/4

8x+2y=12

move the variable to the right side and change the sign.

8x=12-2y

divide both sides of the equation by 8

x=3/2-1/4y

the final solution is

x=3/2-1/4y

4 0
3 years ago
Read 2 more answers
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