Answer:
The answer is A.
You can graph the two inequaltiy just like you would graph slope intercept from. Just think of the inequality sign as an equal sign. :)
Step-by-step explanation:
Answer:
Going from left to right:
1.) Yes
2.) No
3.) Yes
4.) No
5.) No
6.) Yes
7.) No
8.) No
9.) Yes
10.) No
11.) Yes
12.) Yes
13.) No
14.) Yes
15.) Yes
16.) No
Step-by-step explanation:
Functions cannot have any repeating x-coordinates.
Answer:
A
Step-by-step explanation:

as 0≤θ≤90
so θ/2 is also in 0≤θ≤90
hence sin θ/2 and cos θ/2 are positive.
The key features are (a) both f(x) and g(x) include domain values of [3, ∞) and range values of (0, ∞), and both functions are positive for the entire domain.
<h3>How to determine the key features</h3>
The functions are given as:
f(x) = 3x

Next, we enter the above equations in a graphing calculator.
From the graphing calculator, we have:
- The domain of g(x) is [3,∞) and its range is [0,∞)
- The domain of f(x) is (-∞,∞) and its range is (0,∞)
- Both functions have positive values for their domains
By comparing the above highlights, the true statement between functions g(x) and f(x) is option (a)
Read more about function domain and range at:
brainly.com/question/10197594
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What do you mean.
Although I know that 27 2/3 equal 83/3.