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a_sh-v [17]
3 years ago
10

Q is equidistant from the sides of ZTSR. Find mZRST. The

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0

9514 1404 393

Answer:

  40°

Step-by-step explanation:

Triangles QRS and QTS are congruent (HL), so the marked angles are also congruent:

  3x +2 = 4x -4

  6 = x

Then the total angle measure of angle RST is ...

  (3x +2) +(4x -4) = 7x -2 = 7(6) -2 = 40 . . . degrees

m∠RST = 40°

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Please help with my math i took a picture of it
Fynjy0 [20]

Answer:

40°

Step-by-step explanation:

Supplementary angles add up to 180°.  Complementary angles add up to 90°.

m∠1 + m∠2 = 180°

115° + m∠2 = 180°

m∠2 = 65°

m∠2 + m∠3 = 90°

65° + m∠3 = 90°

m∠3 = 25°

m∠2 − m∠3 = 65° − 25° = 40°

6 0
3 years ago
Evaluate the function for the given value of x <br><br><br>f(n)=n^2-6n+7n at n=3 <br><br><br><br>​
vagabundo [1.1K]
F(n)=13
3^2-6(3)+7(3)=12
6 0
3 years ago
Find the area of the circle whose equation is x2+y2=6x-8y​
Semenov [28]

Answer:

Given that the equation of a circle is :

\green{ \boxed{\boxed{\begin{array}{cc}  {x}^{2}  +  {y}^{2}  = 6x - 8y \\  =  >  {x}^{2}  +  {y}^{2}   - 6x + 8y = 0 \\  =  >  {x}^{2}  +  {y}^{2}  + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\  \\  \sf \: standard \: equation \: o f \: circle \: is :  \\   {x}^{2}  +  {x}^{2}  + 2gx + 2fy + c = 0 \\  \\  \sf \: by \: comparing \\  \\ g =  - 3 \\ f = 4 \\ c = 0 \\  \\  \sf \: radius \:  \: r =  \sqrt{ {g}^{2}  +  {f}^{2} - c }  \\  =  \sqrt{ {( - 3)}^{2} +  {4}^{2} - 0  }  \\  =  \sqrt{9 + 16}  \\   = \sqrt{25}  \\  = 5 \: unit \\  \\  \bf \: area \:  = \pi {r}^{2}  \\  = \pi \times  {5}^{2}  \\  =\pink{ 25\pi \:  { unit }^{2} }\end{array}}}}

6 0
3 years ago
Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.Select the option that completes the s
Aneli [31]

Given: Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.

Required: Correct option that complete the statement.

Explanation:

Now, triangle is dilated from the origin at a scale factor of 10.

So, the sides will become larger, but angles will remain the same.

Hence, the triangles will be similar as sides will be in proption (SSS rule).

So, The triangles are similar because their corresponding sides are proptional and their corresponding angles are congurent.

Final Answer: Second group is correct answer.

5 0
1 year ago
A standard brick is 3.625 inches wide, 2.25 inches high, and 7.625 inches long. How many bricks could be in a pallet of bricks t
Snezhnost [94]

Answer: Option D. 1,778

Solution:

Standard brick:

Width: w=3.625 in

Height: h=2.25 in

Length: l=7.625 in

Volumen of one standard brick: v

v=w*h*l

v=(3.625 in)*(2.25 in)*(7.625 in)

v=62.19140625 in^3

Pallet of bricks:

Side: s=4 feet

s=(4 feet)*(12 in / 1 feet)→s=48 in

Volume of a pallet of bricks: V=s^3

V=(48 in)^3

V=110,592 in^3

Number of bricks could be in  a pallet: n

n=V/v

n=(110,592 in^3) / (62.19140625 in^3)

n=1,778.252119

n=1,778

6 0
3 years ago
Read 2 more answers
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