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Rainbow [258]
3 years ago
9

Help Please

Physics
2 answers:
makvit [3.9K]3 years ago
6 0

Hello there,

Question 1 answer: How long someone spent exercising

Question 2 answer: Comparative study

I hope these help, i took the test and they are correct.

Have a good day.

djverab [1.8K]3 years ago
4 0
<span>In this example, what is the independent variable?

a) The time of day assigned to exercise 
<u>b) How long someone spent exercising </u>
c) Type of exercise 
d) How many students are in the class

</span><span>What is the only form of psychological research that can determine cause and effect?

<u>a) Comparative Study </u>
b) Correlational Study 
c) Survey 
d) Experiment</span>
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The right half will be a new bar magnet of 2cm with north pole on the right side and south pole on teh left.
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3 years ago
Three equal point charges, each with charge 1.45 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
LUCKY_DIMON [66]

Answer:

U = 80.91 J

Explanation:

In order to calculate the electric potential energy between the three charges you use the following formula:

U=k\frac{q_1q_2}{r_{1,2}}                  (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q1: q2 charge

r1,2: distance between charges 1 and 2.

For the three charges you have:

U_T=k\frac{q_1q_2}{r_{1,2}}+k\frac{q_1q_3}{r_{1,3}}+k\frac{q_2q_3}{r_{2,3}}           (2)

You use the fact that q1=q2=q3=q and that the distance between charges are equal. Then, in the equation (2) you have:

q = 1.45μC = 1.45*10^-6C

r = 0.700mm = 0.700*10^-3m

U_T=3k\frac{q^2}{r}=3(8.98*10^9Nm^2/C^2)\frac{(1.45*10^{-6}C)}{0.700*10^{-3}m}\\\\U_T=80.91J

The electric potential energy between the three charges is 80.91 J

7 0
3 years ago
During the annual shuffleboard competition, Renee gives her puck an initial speed of 8.12 m/s. Once leaving her stick, the puck
shutvik [7]
<h2>Answer:2.65 seconds</h2>

Explanation:

Let a be the acceleration.

Let u be the initial velocity.

Let v be the final velocity.

Let t be the time taken.

As we know from the equations of motion,

v=u+at

Given,v=0\\u=8.12ms^{-1}\\a=-3.06ms^{-2}

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t=2.65sec

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4 years ago
Which year was pluto no longer considered a planet?.
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In concave lenses a Distance object appears ​
JulsSmile [24]

Answer:

it appears to be farther away than it actually is, and therefore smaller then the object itself.

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3 years ago
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