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devlian [24]
3 years ago
7

Alexa and rose read books that have the same number of pages. Alexa’s book divided into 8 equal chapters.roses book is divided i

nto 6 equal chapters. Each girl has read 3 chapters of her book. Write a fraction to describe what part of the book each girl read. Then tell who read more pages. Explain
Mathematics
1 answer:
Elena-2011 [213]3 years ago
5 0
Let's list out what we already know:
Alexa's book is into 8 chapters
Rose's book is into 6 chapters
So since they are out of how many chapters, they number of chapters their books are split into will be the denominator of each fraction. Each girl has already read 3 chapters, so they'll have 3 as their numerator.
Alexa: 3/8
Rose:3/6
We can see that Rose is already at half of the book while Alexa's half would be 4/8, and she isn't there yet. So Rose read more of her book.
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3 years ago
Factories 25x-35 what would the answer be
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Answer:

Step-by-step explanation:

25x - 35 = 5*5*x - 5*7

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2 years ago
the vertex of the parabola is at the point (2,-4). Which of the following could be this parabola’s equation?
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3 years ago
Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°
mote1985 [20]

Answer:

sin(2\theta)=\frac{\sqrt{35} }{18}

Step-by-step explanation:

Recall the formula for the sine of the double angle:

sin(2\theta)=2*sin(\theta)*cos(\theta)

we know that cos(\theta)=\frac{3}{18}, and that \theta is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what sin(\theta) is:

cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }

With this information, we can now complete the value of the sine of the double angle requested:

sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}

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3 years ago
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