Answer:
Option 4, 64 cm^2
Step-by-step explanation:
The polygon in the shape of a star can be made to be easier to find the area of by cutting it into triangle. For all the "point edges" of the star, we can cut them in half from the vertex to create two right-angled triangles at each edge.
The formula of the area of a triangle is bh/2: the height is given as 6cm, the base is 4cm /2 (after you cut it in half) and so is 2 cm. Since the edges can be cut into two, there are 8 right angled triangles at the edges in total.
To find the area of them:
A=8(bh/2)=8(2*6/2)=48 cm^2
However, we are still missing the part at the centre we haven't found the area of, the square. The area of a square is given by the square of the side length(4cm). Thus, A=4*4=16cm^2
Adding the areas of all the edges and the square:
48 + 16 = 64cm^2
Hence, the area of the polygon is 64cm^2
The slope would represent the cost per minute, since m is the length of the call in minutes. Logically, D) Cost per minute, is the only one that would work. The connection cost would be just added in, and you wouldn't multiply the cost of having a phone line by how many minutes you're on the phone. The length of the call is already there, it's m, so that wouldn't work either. Therefore, D, cost per minute, is the logical answer. The slope in the equation represents D, cost per minute.
Answer:
<u>David will have the most cookies and he will have two cookies more than Jake</u>
Step-by-step explanation:
1. Let's calculate how many cookies will David cut with his cutter, this way:
Number of cookies = Rolls of cookie dough/Size of the segment
Replacing with the values we know:
Number of cookies = 2/(1/8)
Number of cookies = 16
2. Let's calculate how many cookies will Jake cut with his cutter, this way:
Number of cookies = Rolls of cookie dough/Size of the segment
Replacing with the values we know:
Number of cookies = 2/(1/7)
Number of cookies = 14
<u>David will have the most cookies and he will have two cookies more than Jake</u>
The correct answer is 2.5×10^2
Hope this helped :)
