4xy-3y=12
y(4x-3)=12
y=12/(4x-3)
<h3>Given :</h3>
- Distance = 175
- Time 1 = 4 hours

<h3>To find:</h3>
- Different between two speeds when distance is same.

<h3>Solution:</h3>
<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>
In first part we will find speed 1 in which time is 4 hours
we know:-

So:-





<u>Part 2</u>
In first part we will find speed 2 in which time is 3 hours
Again:








<u>Part 3</u>
In this part we will find different between speed 1 and speed 2


So :







Answer:
-5z -13 is answer
Step-by-step explanation:
=15+−5z+−3+−25
Combine Like Terms:
=15+−5z+−3+−25
=(−5z)+(15+−3+−25)
=−5z+−13
bye
I think the answer is D but im not sure