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Gnoma [55]
3 years ago
12

Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: E

quals negative 4 + 6 + 5 Step 3: Equals 7 What, if any, was Jane's mistake?
Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: Equals negative 4 + 6 + 5 Step 3: Equals 7 What, if any, was Jane's mistake?

Jane's evaluation :

x² - 3x + 5 for x = - 2

Step 1:

(-2)² - 3(-2) + 5

Step 2:

-4 + 6 + 5

Step 3 :

= 7

Jane's mistake was in STEP2,

evaluating (-2)² = 4 and not - 4

Hence, (-2)² - 3(-2) + 5

= 4 + 6 + 5

= 15

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<h3>Given :</h3>
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\\  \\

<h3>To find:</h3>
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\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

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\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

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\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

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\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

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