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Gnoma [55]
3 years ago
12

Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: E

quals negative 4 + 6 + 5 Step 3: Equals 7 What, if any, was Jane's mistake?
Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: Equals negative 4 + 6 + 5 Step 3: Equals 7 What, if any, was Jane's mistake?

Jane's evaluation :

x² - 3x + 5 for x = - 2

Step 1:

(-2)² - 3(-2) + 5

Step 2:

-4 + 6 + 5

Step 3 :

= 7

Jane's mistake was in STEP2,

evaluating (-2)² = 4 and not - 4

Hence, (-2)² - 3(-2) + 5

= 4 + 6 + 5

= 15

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(2x-7)-(4x^2+6x-3)+(x^2+4)
masha68 [24]

Answer:

-3x^2-4x

Step-by-step explanation:

Simplify:

\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)

=2x-7-\left(4x^2+6x-3\right)+x^2+4

Group same factor:

=-\left(4x^2+6x-3\right)+x^2+2x-7+4

Add :

=-\left(4x^2+6x-3\right)+x^2+2x-3

Apply the distributive law: -(a+b) = -a - b

-\left(4x^2+6x-3\right)=-4x^2-6x+3

=-4x^2-6x+3+x^2+2x-3

Group same factor:

=-4x^2+x^2-6x+2x+3-3

Subtract:

=-4x^2+x^2-6x+2x

Add:

=-3x^2-6x+2x

Group same factor:

=-3x^2-4x

Hence answer = -3x^2-4x

<u><em>~lenvy~</em></u>

8 0
2 years ago
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Answer:

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5 0
3 years ago
He table shows the solution to the equation |2x − 5| − 2 = 3:
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The solution is completely correct, as putting 5 or 0 in the formula again will make it true.

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4 years ago
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