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Naddika [18.5K]
2 years ago
11

PLEASE HELP WITH THIS

Mathematics
2 answers:
ArbitrLikvidat [17]2 years ago
8 0

Answer:

B

Step-by-step explanation:

The question can be written is

5^x = 75

Now take the log of both sides.

log(5x) = log(75)            Bring the x outside the brackets

x log(5) = log(75)           Divide by log 5

x = log(75)/log(5)

log 75 = 1.8751

log 5 = .8990

x = 1.8751/.8990 = 2.6826

marusya05 [52]2 years ago
7 0

Answer:

  (b)  2.68

Step-by-step explanation:

Your question has a link to a suitable calculator. All you need to do is <em>make use of it</em>. It tells you log₅(75) ≈ 2.68.

__

<em>Other ways to look at the problem</em>

If you recall that <em>a logarithm represents an exponent</em> of the base, you can ask yourself, what power 5 must be raised to in order to get 75. You know that 5^2 = 25, and 5^3 = 125, so the power will have to be between 2 and 3. There is only one answer choice in that range: 2.68.

__

The rules of logarithms let you rewrite the given expression as ...

  log₅(75) = log₅(3×5²) = log₅(3) +2·log₅(5) = log₅(3) +2

The log₅ of any number between 1 and 5 will be a positive fraction, so this sum must be between 2 and 3.

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Jose left the White House and drove toward the recycling plant at an average speed of 40 km/h. Rob left some time later driving
Aleks04 [339]
Let x represent Jose's drived distance and y represent Rob's.
So what you need to do is to solve the equation:
40x=48*5
40x=240
x=240/40=6

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4 0
3 years ago
Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin
Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

A=0.48

B=0.13

AB=0.03

O=0.36

As we know that when A and B both are independent that

P(A and B)= P(A) X P(B)

The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here  four case are possible

So

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

7 0
3 years ago
PLEASE HELP!
Orlov [11]
We have that
<span>If (5x-4+13x=5) -------------->  then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then 
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>


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3 years ago
Slope 2 passing through 10,8
nlexa [21]
Use y=Mx+b    with x=10 and y=8
4 0
3 years ago
I did the first one but can you help me with the second one plz??
yanalaym [24]

the only like-terms are on the right-hand-side, since the left-hand-side has only 1 term anyway.

\bf \cfrac{5}{2}s=\cfrac{3}{2}s+s\implies \cfrac{5}{2}s=\cfrac{3}{2}s+\cfrac{s}{1}\implies \cfrac{5}{2}s=\stackrel{\textit{using the LCD of 2}}{\cfrac{(1)3s+(2)s}{2}} \\\\\\ \cfrac{5}{2}s=\cfrac{3s+2s}{2}\implies \cfrac{5}{2}s = \cfrac{5}{2}s

5 0
3 years ago
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