Is 1.999 an irrational number

2 answers:

7 0

Rational Number. 1.999 is a repeating decimal. Repeating decimals, fractions and whole numbers are all rational numbers.

babymother [125]3 years ago

4 0

No, 1.999 is a rational number.

Hope this helped! :)

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Easy Question pls help. (Algebra II type problems)

Roman55 [17]

Answer:

$\large\boxed{if\ x\neq-3\ \wedge\ y\neq0\ \wedge\ x\neq y\ \wedge\ x\neq -y}$

second

$\large\boxed{y\neq0\ \wedge\ x\neq-y\ (y\neq-x)}$

Step-by-step explanation:

We know that dividing by 0 is impossible.

Therefore, the denominator of the expression must be different from 0.

$\text{For}\\\\\dfrac{(x-y)^2}{2xy+6y}\times\dfrac{4x+12}{x^2-y^2}\\\\\\2xy+6y\neq0\qquad(1)\\\\x^2-y^2\neq0\qquad(2)$

$(1)\\2xy+6y\neq0\qquad\text{distribute}\\\\2y(x+3)\neq0\iff2y\neq0\ \wedge\ x+3\neq0\\\\2y\neq0\qquad\text{divide both sides by 2}\\\boxed{y\neq0}\\\\x+3\neq0\qquad\text{subtract 3 from both sides}\\\boxed{x\neq-3}\\==========================\\(2)\\x^2-y^2\neq0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\(x-y)(x+y)\neq0\iff x-y\neq0\ \wedge\ x+y\neq0\\\boxed{x\neq y}\ \wedge\ \boxed{x\neq-y}$

$\text{For}\\\\\dfrac{2(x-y)}{y(x+y)}\\\\y(x+y)\neq0\iff y\neq0 \wedge\ x+y\neq0\\\\ \boxed{y\neq0}\ \wedge\ \boxed{x\neq-y}$

3 0

3 years ago

Select the correct answer from each drop-down menu. Factor the expression 8x3y − 8x2y − 30xy. 8x3y − 8x2y − 30xy = ( )( )

pychu [463]

Answer:

$8x^3y-8x^2y-30xy=2xy(2x+3)(2x-5)$

Step-by-step explanation:

we are given an expression as

$8x^3y-8x^2y-30xy$

Firstly, we will find factors

$(2xy)\times 4x^2-(2xy)\times 4x-(2xy)\times 15$

We can see that 2xy is common in all terms

so, we can factor out 2xy from all terms

and we get

$8x^3y-8x^2y-30xy=2xy(4x^2-4x-15)$

now, we can factor again

$4x^2-4x-15=(2x+3)(2x-5)$

we get

$8x^3y-8x^2y-30xy=2xy(2x+3)(2x-5)$

8 0

4 years ago

Simplify 2/x+3 - 3/x-5

Arada [10]

First, you should equalize the denominator of first and second fraction. If the denominator multiplies by (x-5), so does the numerator. If the denominator multiplies by (x+3), so does the numerator.
(Look into my attachment at the second row)

Second, simplify the algebraic form for the numerator.
(Look into my attachment at the fourth row)

Third, simplify the denominator
(Look into my attachment at the last row)