When added, these two angles are supplementary, meaning that their sum is 180. This means that we can do the following to find x, and eventually DBC:
3x+67+4x+50=180
Simplifies to:
7x+117=180
Then by the Subtraction Prop. of Equality:
7x=63
Then divide by 7 on both sides to get that x=9.
We then substitute 9 into angle DBC.
4(9)+50
=36+50
DBC=86
:)
19/20
19/20 = 0.95
0.9 < 0.95
{(-2, 6), (-5, -1), (3, 7), (-5, 0)}
Domain: The domain is all the x-values (-2, -5, 3, -5)
Range: The range is all the y-values (6, -1, 7, 0)
Function: It's not a function because of the x-value -5 is repeating.
Answer:
6.25n + 3.50
$34.75
Step-by-step explanation:
Break down the important information given in the problem.
The one-time delivery fee is 3.50. This is only paid one time an never again, making it the <u>constant</u>, a number that does not change.
Each lunch costs 6.25. This amount will increase depending on how many times Mr. Jackson orders lunches, "n" times. This number is the <u>rate</u> because it changes. The rate is attached to the variable.
If you add the amounts together, that is the total cost of ordering lunches.
6.25n + 3.50
(Reember expressions do not have the equal sign).
To find the cost of ordering 5 lunches, use the expression. Substitute "n" for 5 because "n" represents the number of lunches ordered.
6.25n + 3.50
= 6.25(5) + 3.50 Simplify by multiplying 5 and 6.25
= 31.25 + 3.50 Add the two values
= 34.75 Total cost of 5 lunches
Therefore the cost of ordering 5 lunches is $34.75.
Answer:
18
Step-by-step explanation:
