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DiKsa [7]
3 years ago
6

Two forces, one of 120 pounds and the other of 200 pounds, act on the same

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0

9514 1404 393

Answer:

  -8.21°

Step-by-step explanation:

The horizontal and vertical components of the forces are ...

  (120; 30°) = (103.923, 60}

  (200; -30°) = (173.205, -100}

Then the resultant is ...

  (103.923 +173.205, 60-100) = (277.128, -40)

and the resultant direction is

  arctan(-40/277.128) = -8.21°

_____

The polar coordinates (A; β) can be translated to rectangular coordinates by ...

  (A; β) = (A·cos(β), A·sin(β))

__

<em>Additional comment</em>

The semicolon in (A; β) signifies the ordered pair is polar coordinates (magnitude; angle). The comma in (x, y) signifies the ordered pair is rectangular (Cartesian) coordinates. This notation is borrowed from the GeoGebra app, a geometry graphing/calculating program. It avoids some confusion. Personally, I prefer the notation A∠β to signify a magnitude and direction in polar coordinates.

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Answer:

90 in^{2}

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

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Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

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whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

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What is required to name a plane
Ludmilka [50]
You need three non-collinear points to name a plane. 

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2 years ago
Sets<br> Let A = {1, 2, 3, 8} and {x | x is an even whole number less than 9}, find An B <br>​
spin [16.1K]
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B={x|x is an even whole no less than 9}

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Now

\\ \sf\longmapsto A\cap B=\{2,8\}

6 0
2 years ago
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