(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Good evening ,
Answer:
<h2>153 dimes.</h2>
Step-by-step explanation:
1+2+3+...+17 = (17×18)/2 = (17×18)÷2 = 153 dimes.
it’s the sum of 17 terms of a geometric series.
:)
Answer:
**The total length of his drive is 25 miles
Step-by-step explanation:
15 = 3/5
therefore 5 miles is 1/5 of the way home
15+5+5=25
14 my teacher just told me the answer
A. -3+4i Square both numbers, add them, then find the square root. Essentially, use the Pythagorean theorem. -3^2 + 4^2 9 + 16=25 Square root of 25 is 5.
