Answer:
A. Similar - AA
Step-by-step explanation:
The given parameters of ΔPQR and ΔXYZ are;
In ΔPQR, we have; PQ = 3, PR = 5, and ∠PQR = 80°
In ΔXYZ, we have; XY = 6, XZ = 10, and ∠XYZ = 80°
In ΔPQR, by sine rule, we have;
3/(sin(∠PRQ)) = 5/(sin(80°))
sin(∠PRQ) = (3/5) × sin(80°)
∴ ∠PRQ = arc sin((3/5) × sin(80°))
In ΔXYZ, by sine rule, we have;
6/(sin(∠XZY)) = 10/(sin(80°))
sin(∠XZY) = (6/10) × sin(80°) = (3/5) × sin(80°)
∴ ∠XZY = arc sin((3/5) × sin(80°))
∠PRQ = ∠XZY by transitive property of equality
Therefore in ΔPQR and ΔXYZ, we have;
∠PRQ = ∠XZY and ∠PQR = ∠XYZ
Therefore, ΔPQR is similar to ΔXYZ by Angle Angle, AA, similarity postulate.
