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AnnZ [28]
4 years ago
6

Stephanie first jump at track competition was 9 1/3. On her second try she jumped 1 1/6 feet farther than her first jump. What e

quationsis used to determine the distance Stephanie jumped on her second try
Mathematics
2 answers:
STALIN [3.7K]4 years ago
7 0

Answer:

9 1/3 + 1 1/6

Step-by-step explanation:

9 1/3 + 1 1/6  Since she jumped 1 1/6 ft farther she added 1 1/6 ft.

NeTakaya4 years ago
3 0

Answer:

1 1/6 + 9 1/3.

Step-by-step explanation:

The second jump is 1 1/6 of a foot farther than her first jump, so add 1 1/6 to 9 1/3.

The equation would be 1 1/6 + 9 1/3.

If you wanted improper fractions, they would be 7/6 + 28/3. (converting to improper fraction you multiply the whole number by the denominator and add the numerator and put that over the denominator).

You might be interested in
A 10-foot ladder leans against a wall with its foot braced 3 feet from wall's base. How far up the wall does the ladder reach?
dlinn [17]
Pythagorean theorem
for a right triangle with legs legnth a and b and hytponuse c
a^2+b^2=c^2

the legnht of th eladder is the hypotnuse
the 3 feet is bottom leg
height is other leg

10=c
3=a
b=?
3^2+b^2=10^2
9+b^2=100
minus 9 both sides
b^2=91
sqrt both sides
b=√91
aprox
b=9.53939


answer is √91 feet or aprox 9.53939
8 0
3 years ago
9 ones 2 thousands -3ones
Andrew [12]
2,000(two thousands)+ 9(nine ones)=2,009. But, - 3(three ones)= 2,006
7 0
4 years ago
Find the solution set
kow [346]
Hope this would help you

5 0
4 years ago
In the expansion of ( x^3 - 2/x^2 ) ^10 , find the coefficient of 1/x^5​
Lilit [14]

Answer:

240

Step-by-step explanation:

We need to find the coeffeicent of the binomial expansion of

( {x}^{3}  - 2 {x}^{ - 2} ) {}^{10}

Note that

- 2 {x}^{ - 2}  = -  \frac{2}{ {x}^{2} }

The binomial theorem states that

(x + y) {}^{n}  = x {}^{n} y {}^{0}  +  \binom{n}{1} x {}^{n - 1} y +  \binom{n}{2} x {}^{n - 2} y {}^{2} ....... + x {}^{0} y {}^{n} ( \binom{n}{n} )

Using this, we let expand our series

( {x}^{3}   - 2 {x}^{ - 2} ) {}^{10}  = x {}^{30}  +  \binom{10}{1} ( {x}^{27}     2 {x}^{ - 2} ) +  \binom{10}{2}  {x}^{24} 2x {}^{ - 4}  +  \binom{10}{3}  {x}^{21} 2x {}^{ - 6}  +  \binom{10}{4}  {x}^{18} 2x { }^{ - 8}  +  \binom{10}{5} x {}^{15} 2x {}^{ - 10}  +  \binom{10}{6} x {}^{12}2 x {}^{ - 12}  +  \binom{10}{7} x {}^{ 9} 2x {}^{ - 14}  +  \binom{10}{8} x {}^{ 6} 2x {}^{ - 16}  +  \binom{10}{9} ( {x}^{3} )2x {}^{ - 18}  + 2x {}^{ - 20}

\frac{1}{ {x}^{5} }  = x {}^{ - 5}

So what term in the series eqaul x^-5.

That term is the 10 choose 7 term.

\binom{10}{7}  {x}^{9} 2x {}^{ - 14}

Because

=  \binom{10}{7} 2x {}^{ - 14}  {x}^{9}  =  \binom{10}{7} 2 {x}^{ - 5}

So we need to compute 10 choose 7.

That equals

10!/3!(7!)= 10×9×8/6= 720/6=120.

So we get

120(2) {x}^{ - 5}

240 {x}^{ - 5}

So the coeffceint u

is 240

3 0
3 years ago
4p - p-p + 2p =<br><br> 5x + 3y + 4z - 3x + 3z - 5y
earnstyle [38]

Answer:

69

Step-by-step explanation:

i added all of it

4 0
3 years ago
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