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3 years ago

A 10-foot ladder leans against a wall with its foot braced 3 feet from wall's base. How far up the wall does the ladder reach?

1 answer:

8 0

Pythagorean theorem
for a right triangle with legs legnth a and b and hytponuse c
a^2+b^2=c^2

the legnht of th eladder is the hypotnuse
the 3 feet is bottom leg
height is other leg

10=c
3=a
b=?
3^2+b^2=10^2
9+b^2=100
minus 9 both sides
b^2=91
sqrt both sides
b=√91
aprox
b=9.53939

answer is √91 feet or aprox 9.53939

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ipn [44]

Hello,

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r'=5(-sin t)

r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
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A random number generator is used to select an integer from 1 to 100 (inclusively). What is the probability of selecting the in

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The correct answer is zero.

Step-by-step explanation:

A random variable generator selects an integer from 1 to 100 both inclusive leaves us with total number of possible sample as 101.

We need to find the probability of selecting the integer 194.

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3 years ago

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3 years ago

Read 2 more answers

Laura lives 15 miles east of Kevin’s place. Kevin lives 8 miles south of Michelle’s place. How far does Michelle live from Laura

My name is Ann [436]

Answer:

17 miles.

Step-by-step explanation:

Let's define:

North as the positive y-axis

East as the positive x-axis.

We know that Laura lives 15 miles east of Kevin's place.

Kevin lives 8 miles south of Michelle's place.

So, if we define the origin, (0, 0) as Laura's place.

From:

"that Laura lives 15 miles east of Kevin's place."

We have that the location of Kevin's house is 15 miles west from Laura's place, then Kevin's house is at:

(0, 0) + (-15mi, 0) = (-15mi, 0)

From Kevin lives 8 miles south of Michelle's place, we know that Michelle's live 8 miles north of Kevin's place.

Then the location of Michele's house is the location of Kevin's plus (0, 8mi).

Michelle's house is located at:

(-15mi, 0) + (0, 8mi) =(-15mi, 8mi)

Now we want to find the distance between Michelle's house and Laura's house.

Michelle's house is at (-15mi, 8mi)

Laura's house is at (0mi, 0mi)

Remember that the distance between two points (a, b) and (c, d) is given by:

$D = \sqrt{(a - c)^2 + (b - d)^2}$

Then the distance between (-15mi, 8mi) and (0mi, 0mi) is:

$D = \sqrt{(-15mi - 0mi)^2 + (8mi - 0mi)^2} = 17mi$

The correct option is the first one, 17 miles.

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3 years ago