A 10-foot ladder leans against a wall with its foot braced 3 feet from wall's base. How far up the wall does the ladder reach?
1 answer:
Pythagorean theorem
for a right triangle with legs legnth a and b and hytponuse c
a^2+b^2=c^2
the legnht of th eladder is the hypotnuse
the 3 feet is bottom leg
height is other leg
10=c
3=a
b=?
3^2+b^2=10^2
9+b^2=100
minus 9 both sides
b^2=91
sqrt both sides
b=√91
aprox
b=9.53939
answer is √91 feet or aprox 9.53939
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Answer:
(X1,y1)=(-5,-3)
(x2,y2)=(1,3)
Step-by-step explanation:
xsquared+5x-3-x=2
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