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3 years ago

13

What is the product? image attached

1 answer:

LenKa [72]3 years ago

5 0

The Answer choice would be A

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shiny shampoo bottle cost 6.98 for a 14 oz bottle. A 28 oz bottle of shiny shampoo cost 19.99 you have a 2.00 coupon good on any

AleksandrR [38]

ANSWER= 14 oz bottle

6.98 - 2 = 4.98 (14oz)
19.99 - 2 = 17.99 (28oz)

28 is triple the price when it’s only two times bigger

4 0

3 years ago

I need help please and thank you

Ira Lisetskai [31]

This is a false statement.

When you are solving using square roots, you need to be aware that answers can be both positive and negative. When we solve this, you see there are two possible answers.

x^2 - 9 = 0

x^2 = 9

x = +/- 3

While 3 is an answer, so is -3. If we square either of those numbers, we get 9, which will satisfy the equation.

5 0

3 years ago

Is ATAG-ABAG? If so, identify the similarity postulate or theorem that

zaharov [31]

Answer: it’s D

Step-by-step explanation:

7 0

3 years ago

Here we will study the function f (x) = e ^ x sin (x), where x ∈ [0, 2π]. a) Determine where the function is decreasing and incr

Semmy [17]

fff

$f(x) = e^x sin (x)$

To find increasing and decreasing intervals we take derivative

$f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)$

Now we set the derivative =0 and solve for x

$e^x(sinx+cosx)=0$

sinx + cosx =0

divide whole equation by cos x

$\frac{sinx}{cosx} + \frac{cosx}{cosx} =0$

tanx +1 =0

tanx = 1

$x=\frac{3\pi }{4}$ and $x=\frac{7\pi}{4}$

Now we pick a number between 0 to $\frac{3\pi }{4}$

Lets pick $\frac{\pi }{2}$

Plug it into the derivative

$f'(x) =e^{\frac{\pi }{2}}(sin(\frac{\pi}{2})+cos(\frac{\pi }{2}))$

= 4.810 is positive

So the graph of f(x) is increasing on the interval [0, $x=\frac{3\pi }{4}$ )

Now we pick a number between $\frac{7\pi}{4}$ to 2pi

Lets pick $\frac{11\pi}{6}$

Plug it into the derivative

$f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))$

= 116 is positive

So the graph of f(x) is increasing on the interval $(\frac{7\pi }{4}, 2\pi)$

Increasing interval is $(0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)$

Decreasing interval is $(\frac{3\pi}{4}, \frac{7\pi}{4})$

(b)

The graph of f(x) increases and reaches a local maximum at $x=\frac{3\pi}{4}$

The graph of f(x) decreases and reaches a local minimum at $x=\frac{7\pi}{4}$

(c)

f(0) = 0

$f(2\pi)=0$

$f(\frac{3\pi }{4})=7.46$

$f(\frac{7\pi}{4})=-172.64$

Here global maximum at $x=\frac{3\pi}{4}$

Here global minimum at $x=\frac{7\pi}{4}$

3 0

3 years ago

Read 2 more answers

6. Evaluate the following expression: 10 + 4(6-2)<br> А. 56<br> B. 82<br> С. 18<br> D. 26

irakobra [83]

Answer:

D. 26

Step-by-step explanation:

$10+4(6-2)\\10+4(4)\\10+16\\26$

7 0

3 years ago

Read 2 more answers