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3 years ago

Determine ƒ(–a) where ƒ(x) = x2– 6x and simplify.

1 answer:

6 0

Please use "^" to denote exponentiation: f(x) = x^2 - 6x.

To find f(-a), replace "x" with "(-a)" in the function (x) = x^2 - 6x:

f(-a) = (-a)^2 - 6(-a) = a^2 + 6a (answer)

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Solve the equation <br>8(4- x) = 7x + 2<br>x=

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Answer: x=2

Step-by-step explanation:

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32−8x=7x+2

Add 8x to both sides.

32=7x+2+8x

Simplify 7x+2+8x7x+2+8x to 15x+215x+2.

32=15x+2

Subtract 22 from both sides.

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Simplify 32−2 to 30.

30=15x

Divide both sides by 15.

30/15=x

Simplify 30/15 to 2

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Switch sides.

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Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8

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Given:

The function are

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$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

$(f\circ g)(1)=f(\sqrt{1})$ $[\because g(x)=\sqrt{x}]$

$(f\circ g)(1)=f(1)$

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$(f\circ g)(1)=1-1$

$(f\circ g)(1)=0$

The value of $(f\circ g)(1)$ is 0.

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