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tangare [24]
4 years ago
14

Signals can be transmitted in one of two ways. list and explain both

Computers and Technology
1 answer:
S_A_V [24]4 years ago
3 0
I'm owning a give you one review trouble into the brave explain how you didn't war in the air might help you do the answer so you could go and do that
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What are three good things and three bad things about the metal pewter
Setler79 [48]
Good things:
It is a solid material,NOT plated which makes it easily engravable.
does not tarnish or
discolor easily

Bad things:
It is not a high quality metal
It will melt at low temperatures,so do not get it around extreme heat.
It can damage easy if exposed to acids like lemon juice or vinager


4 0
4 years ago
If you need to multiply 50 and 8 and divide by 2, what would you type on the numerlc keypad?
nata0808 [166]

Answer:

50*8/2

The asterisk is the multiplication sign and the parenthesis is the division.

I've never used an apostrophe for a multiplication sign before, but I'm guessing multiplication is what it stands for.

Explanation:

4 0
3 years ago
Write a program named as calcPrice.c that formats product information entered by the user and calculate the total amount of purc
Colt1911 [192]

Answer:

Here is the calcPrice.c program:

#include <stdio.h>   //to use input output functions

int main(void)  {  //start of main method

   int itemNo, month, day, year, quantity;  //declares variables to hold item number, quantity, and date

   float unitPrice; //declare variable to hold price per unit

   printf("Enter item number: ");  // prompts user to enter item number

   scanf("%d", &itemNo);  //reads item number from user and stores it in itemNo variable

   printf("Enter unit price: ");  // prompts user to enter unit price

   scanf("%f", &unitPrice);  //reads input unit price and stores it in unitPrice variable

   

    printf("Enter quantity: ");  //prompts user to enter quantity

   scanf("%d", &quantity);  //reads input quantity and stores it in quantity variable

   printf("Enter purchase date (mm/dd/yyyy): ");  //prompts user to enter purchase date

   scanf("%d/%d/%d", &month, &day, &year);  //reads input date and stores it in month, day and year variables

    float totalAmount = unitPrice * quantity;  //computes the total amount

   printf("\nItem\tUnit Price\tQTY\tPurchase Date\tTotal Amount\n");  //displays the item, unit price, qty, purchase data and total amount with tab space between each

   printf("%d\t$%5.2f\t%d\t%.2d/%.2d/%d\t$%5.2f\n", itemNo, unitPrice,quantity, month, day, year,totalAmount);   }    //displays the values of itemNo, unitPrice, quantity, month, day, year and computed totalAmount with tab space between each

Explanation:

Lets suppose user enters 583 as item number, 13.5 as unit price, 2 as quantity and 09/15/2016 as date so

itemNo = 583

unitPrice = 13.5

quantity = 2

month = 09

day = 15

year = 2016

totalAmount is computed as:

  totalAmount = unitPrice * quantity;

 totalAmount = 13.5* 2

totalAmount = 27.00

Hence the output of the entire program is:

Item    Unit Price      QTY     Purchase Date   Total Amount      

583     $  13.50           2           09/15/2016         $  27.00  

The screenshot of the program along with its output is attached.

4 0
3 years ago
4.14 LAB: Countdown until matching digits In C++ Write a program that takes in an integer in the range 20-98 as input. The outpu
Fantom [35]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

using namespace std;   // to identify objects like cin cout

int main() { //start of main function

   int number;  //an integer value

   cout<<"Enter an integer: ";  //prompts user to enter a number

   cin >> number;  // reads integer value from user

   if (number > 98 || number < 20) {  //if number is not between 20 and 98

  cout<<"Input must be 20-98";   }  //display this message if number is not between 20 and 98

 else {  // if number is in range 20-98

   while(number%11){  // loop keeps taking mod of input number with 11 until matching digits found

       cout<<number<<" ";  //displays the numbers

       number--;     }  // decrements the value of number by 1

    cout<<number<<" "; }  } // displays the matching digits

Explanation:

I will explain the program with an example:

Let suppose the number = 90

The if condition evaluate to false because 90 is in the range of 20-98 so the else part executes which has a while loop that works as following:

while(number % 11)

At first iteration:

This while(number % 11) is basically equivalent to :

while(number % 11 != 0)

while(90 % 11)

The % operator is the modulo operator which returns the remainder of the division. So when 90 is divided by 11 the remainder is 2. This is not equal to 0. So the statement under while condition executes:

cout<<number<<" "; This statement displays the number on output screen. Since number = 90 so 90 is printed. " " adds a space with the number

90

Next the value of number is decremented to 1 so number = 89

At second iteration:

while(number % 11) becomes:

while(89 % 11)

When 89 is divided by 11 the remainder is 1. This is not equal to 0. So the statement under while condition executes:

cout<<number<<" "; This statement displays the number on output screen. Since number = 89 so 89 is printed. " " adds a space with the number

90 89

Next the value of number is decremented to 1 so number = 88

At third iteration:

while(number % 11) becomes:

while(88 % 11)

When 89 is divided by 11 the remainder is 0. So the while loop breaks because the condition while(number % 11 != 0) evaluates to false. So the statement in while loop does not execute and program control moves to the following statement:

    cout<<number<<" "; This statement displays that number whose digits match on the output screen with a space. So the output of the entire program is:

90 89 88

The program along with the output using example given in the question i.e. input is 93 is attached in a screenshot.

6 0
3 years ago
Where can I learn how to make my own video game for free?
Sladkaya [172]
Game’s top rack not top pop
4 0
3 years ago
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