Question

A rectangle has a perimeter of 48m. The width is 2m less than the length. Using an equation find the dimensions.

Answer 1

Ok so we know that the total perimeter of the rectangle is 48m.

We also know that to get the perimeter, it is the sum of two lengths and two widths.

Therefore 2L + 2W = 48

However, we also know that the width is 2m less than the length, so the above equation can be rewritten as:
2L + 2(L-2) = 48

We can simplify this to make it
4L - 4 = 48
So 4L = 52
Hence L = 13.

We know that the width is 13-2, so the width is 11.

So the length is 13m and the width is 11m

Hope this helped