Okay, here we have this:
Considering the provided information, we are going to calculate the requested rate of change, so we obtain the following:
We will replace in the rate of change formula with the following points: (1990, 1.2) and (1994, 1.6), then we have:
Rate of change=(f(b)-f(a))/(b-a)
Rate of change=(1.6-1.2)/(1994-1990)
Rate of change=0.4/4
Rate of change=0.1 Billion
Finally we obtain that the average rate of change in the number of public library visits from 1990 to 1994 is 0.1 billion.
Answer
Find out the what is the effective cost per year of the extended warranty .
To proof
As given
The extended warranty on a $960 dishwasher is 21% of the purchase price and lasts for eight years.
21% is written in the decimal form
= 0.21
effective cost for the extended warranty = 0.21 × 960
= $ 201.6
= $25.2
Therefore the
effective cost per year of the extended warranty be $25.2
Option (d) is correct .
Hence proved
Question:
The options are;
A. The distances in the Olympic final were farther on average.
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
C. The distances in the Olympic final were all greater than the US qualifier distances
D. none of the above
Answer:
The correct option is;
A. The distances in the Olympic final were farther on average.
Step-by-step explanation:
From the options given, we have
A. The distances in the Olympic final were farther on average.
This is true as the sum of the 5 points divided by 5 is more in the Olympic final
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier
C. The distances in the Olympic final were all greater than the US qualifier distances
This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final
D. none of the above
We have seen a possible correct option in option A
Answer:
The probability that a randomly selected student has a score between 350 and 550 = 0.5867
Step-by-step explanation:
Mean = 500
Standard deviation = 110
Let X be the score of student in a standardized test
The probability that a randomly selected student has a score between 350 and 550 =
=
= Putting
=
= 0.6736 - .0869 ( Using Z table )
= 0.5867