Answer:
a) The fifth pulse rate = 71
b) As shown in this question, (n-1) variables can be assigned freely, but last one has to now be determined, just like I did with the problem in (a).
Explanation:
Mean/average = (Σx)/N
The average is the sum of variables divided by the number of variables
x = each variable
N = number of variables = 5
Mean = 86
Let the unknown pulse rate be y
86 = (94 + 91 + 85 + 89 + y)/5
y = 430 - (94 + 91 + 85 + 89) = 71
b) As shown in this question, (n-1) variables can be assigned freely, but last one has to now be determined, just like I did with the problem in (a).