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VLD [36.1K]
3 years ago
13

The Spanning Tree Protocol operates at the Network layer of the OSI model.

Computers and Technology
1 answer:
BigorU [14]3 years ago
6 0

Answer:

False

Explanation:

The Spanning Tree Protocol operates at the Data link layer of the OSI model.

Spanning Tree Protocol (STP) is a bridge and switch (Layer 2 protocol). The STP specification is IEEE 802.1D. STP's primary aim is to guarantee that when you have redundant routes in your network, you do not generate loops. Loops to a network are fatal.

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Assume that nextWord is a String variable that has been given a String value consisting entirely of letters. Write some Java cod
wel

Answer:

The code example is given below with explanation in c++ language.

Explanation:

Comments will explain what's going on in the code. Below code is already compiled and tested.

#include <time.h>

#include <iostream>

#include <sstream>

using namespace std;

int main(void)

{

//defining start and end time variable

// which will be used to break the infinte loop

   time_t endwait;

   time_t start = time(NULL);

   time_t seconds = 3; // end loop after this time has elapsed

cout<<"Input your number :";

long userNum;

cin>> userNum;

// initializing end time by adding seconds with start time

   endwait = start + seconds;

   // defining outputString which will concatenate all the  

   // divisible numbers in loop

string outputString="";

// bool isCompleted will use to check whether our  

// loop breaks successfully or time is expired.

bool isCompleted=true;

// iterate loop until it comes to 1. as in loop

// the program already displayed the 1 value.

   while (userNum>1)

   {  

  // checking start and end time comparison to  

  // break the infinite loop after some seconds

    if(start >= endwait){

     cout<< "Program end never reached.";

     isCompleted=false;

     break;

 }

 

    userNum=userNum/2;

   // defining stringstream to convert from long to string

    stringstream longToString;

    longToString<<userNum;

  // concatenating all the values

    outputString = outputString + longToString.str()+" ";

   // re initializing the start time with current time.

       start = time(NULL);

   }

   

  // check if while loop breaks successfully then print the

   // series of numbers here.

   if(isCompleted) {

    cout << outputString;

}

   return 0;

}

8 0
3 years ago
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