The equation of line having slope m and y-intercept b is
y = m x + b
The other two equations of line in the same family having intercepts p and q are,keeping the slope same i.e m , described in the question are
→ y= m x + p
→ y = m x + q
As both the equation have same slope i.e m , so lines will be parallel, but their Y - intercept are different i.e distance from the origin where it cuts the y-axis are different i.e at a distance of p and q from origin.
The answer is B because you will cancel the x^5 part on top and bottom and the numerator left 6^3 and denominator left 6 6^3=216divid by 6 you will get 36
To be perpendicular to x = 4, the line must be y = something. This eliminates answer choices #2 and #4. Also, to pass through the point (.5, 7), the line must be y = 7.
So answer choice #3.
Hope this helps!! Let me know if you have ANY questions.