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aivan3 [116]
3 years ago
5

Solve the system of two equations in two variables.

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

no solution

Step-by-step explanation:

all work is shown

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What is 12 decreased by p?
dsp73

Answer:

12 - p

Step-by-step explanation:

12 - p

8 0
3 years ago
Can you kindly help me out please?!
Mila [183]

Answer:

32h^7

Step-by-step explanation:

(4h^4)3=64h^12

64h^12/2h^5=

32h^12/2h^5=32h^7

Hope this helps :)

5 0
3 years ago
-5 x -6=?<br> -90<br> 90<br> -30<br> 30
Natali5045456 [20]

Answer:

30

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7
kozerog [31]

Answer:

x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}

Step-by-step explanation:

<u>Given quadratic equation</u>:

y = x^2 - 6x+7

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7

\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7

\implies y = x^2 - 6x+9-9+7

Factor the perfect square trinomial:

\implies y=(x-3)^2-9+7

\implies y=(x-3)^2-2

To solve the quadratic, set it to zero and solve for x:

\implies (x-3)^2-2=0

\implies (x-3)^2-2+2=0+2

\implies (x-3)^2=2

\implies \sqrt{(x-3)^2}=\sqrt{2}

\implies x-3= \pm\sqrt{2}

\implies x-3+3= 3\pm\sqrt{2}

\implies x= 3\pm\sqrt{2}

Therefore, the solution to the given quadratic equation is:

x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}

6 0
1 year ago
Read 2 more answers
Write a quadratic equation with roots of
stepladder [879]
If the roots are 1 and 3, the factors of this quadratic are (x-1) and (x-3).
The polynomial is x^2 - 4x + 3.

If you were supposed to write a polynomial based upon all four given roots, then:

Looks as tho' you have four distinct roots.  The 4th order polynomial with these roots is f(x) = (x-1)(x-3)(x-7)(x-2).  Multiply this out, combine like terms and then arrange the terms in descending order by powers of x.

6 0
3 years ago
Read 2 more answers
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