Answer: (0.00306,0.00334)
Step-by-step explanation:
Given : Sample size : n= 420000
The number of users developed cancer of the brain or nervous system =134
Then , the proportion of users developed cancer of the brain or nervous system :

Significance level : 
Critical value : 
The confidence interval for population proportion is given by :-

Hence, the 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system is (0.00306,0.00334).
Answer: $9.87
Step-by-step explanation: To find the average add both 15.84 + 3.9 and you get 19.74
Divide 19.74 by 2 you get $9.87
~ Komaljeet (I hope this helped) ♥
567,433 rounded to the nearest hundred thousandth is 600,000.
La longitud del arco (s) en una circunferencia, conociendo el radio (r) y el ángulo (θ) que forman los dos radios, es:
s = r∙θ
Con el ángulo en radianes
F V7 w7 :